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 Calculating Dates in Statit Abstract: Statit provides a family of functions for performing date computations. One of the most powerful of these is the setintrvl() function. The setintrvl() function returns a Statit date or time value that is a specified number of intervals from a particular date or time. We illustrate this function for the problem of finding the date for Friday last (or today if today is Friday). Date computations are always a bit tricky with the Gregorian calendar. This is why Statit uses Julian dates for all date values and computations. A Julian date in Statit is simply the number of days since December 31, 1899. For example, in Statit a Julian date of 1 is January 1, 1900, and a Julian date of 36525 is January 1, 2000. Dates prior to December 31, 1899 are simply negative values. For example, July 4, 1776 is -45104. The value date range for Statit is from January 1, 1753 to December 31, 2199. Statit provides a family of functions for performing date computations. One of the most powerful of these is the setintrvl() function. The setintrvl() function returns a Statit date or time value that is a specified number of intervals from a particular date or time. For example, setintrvl(3,'10-apr-2000',0) will return a date value of April 1, 2000, which is the beginning of the month. The first parameter, 3, specifies that the interval will be in months and the third parameter, 0, is the number of intervals. When the number of intervals is 0, the beginning of the interval is returned. Weeks are another possible interval; e.g., setintrvl(2,'10-apr-2000',3) will return the date that is forward 3 weeks, May 01, 2000. The first parameter, 2, specifies that the interval will be in weeks. Now back to the problem of determining the date for Friday. This can be done with a single command: let friday = (day(2) >= 6) * (setintrvl(2,day(4),0)+5) + ;              (day(2) < 6) * (setintrvl(2,day(4),0)-2) This command uses the day() and setintrvl() functions. The day() function with a parameter of 2 returns the current day of the week, where 1=Sunday and 7=Saturday. The day() function with a parameter of 4 returns today's date. The relational expression, day(2) >= 6, will result in a value of 1 if today is Friday or Saturday and 0 otherwise. Similarly, day(2) < 6, will result in a value of 1 if today is from Sunday to Thursday and 0 otherwise. We can use the result of this relational expression as a multiplier to apply logic to another part of the computational expression. The next part of the expression, setintrvl(2,day(4),0), returns the first day of the current week, which is Sunday. If the current day is Friday or Saturday, then we will add 5 days to this Sunday which will be Friday. Otherwise, we will subtract 2 days from Sunday which will be the previous Friday. The resulting date will be stored with its Statit Julian value in the variable Friday. A print format can be assigned to display the value with a date format: printformat friday lo to hi = "%11j" There you have it. This illustrates how Statit's date functions can be used to solve a complex date computation. For more information, refer to the online documentation for these functions. If you would like additional information, please call our Support staff at statit.support@conduent.com.
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