Q. We recently made some process changes.
How can we determine whether these changes had
a significant impact on our process quality?
A. There are several different tools
for visualizing and testing the efficacy of
process changes. Control charts with phases
are useful, and box plots and t-test comparisons
can be used to determine the significance of
the process change. To use these tools, it is
necessary to assign a variable to indicate which
observations are from the original process and
which observations are from the changed process.
For example, create a variable called "Process,"
where "Old" indicates the original
process and "New" represents the changed
process. This variable can then be used to group
the data into two individual phases.
The following chart shows a process with a
target width of 85. The first ten points are
the original process and the second ten points
are the changed process. Using this chart, it
is difficult to determine whether or not the
process changes were effective since the center
line and the control limits are calculated using
data from both processes.
Hover over data points
to see data values and tips
To more clearly see any differences that occurred
based on your change in the process, a control
chart with Phases is recommended. Using Statit
products, this can be easily implemented by
clicking on the "Phases" buttons in
the control chart dialog. In the Phases dialog,
click the "Calculation categorical variable"
box and select the "Process" variable
to distinguish the individual phases. Based
on this control chart, we can see that the center
line of the new process has apparently shifted
downward somewhat, closer to the target width
of 85.
Hover over data points
to see data values and tips
As with other statistical processes, a shift
that is visible on a chart may or may not be
statistically significant, depending on the
amount of data and its variability. The box
plot clearly shows the location and spread of
the data. In the box plot below, the data variable
is Width and the data is grouped by Process.
Hover over data points
to see data values and tips
From the box plot, it appears that the variances
of the two processes are about the same. At
the same time, it appears that the median may
have decreased a bit. These hypotheses can be
tested easily using the standard statistical
tests.
To test whether the mean has changed, a standard
two-sample t-test is performed. This test is
found under Statistics > One and Two-Sample
Inference > Two-Sample > Compare Location.
The Width variable is tested against the Groups
defined by the Process variable ("Old"
versus "New"). The results are shown
below:
Student's
t-test for Variables:
Width (Old)
N = 50
Width (New)
N = 50
Width (Old) 130
Width
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70
At least one of these samples is
quite skewed, and thus the population
means may not be very useful as measures
of location. It might be better to make
some transformation of the data, such
as logarithmic, before this type of analysis.
The procedure 'compare' provides
diagnostics and suggests options.
However, if one nevertheless wants
inference about the means, the t-test
is not highly sensitive to lack of normality.
There is no significant difference
between the means.
If in fact the populations
means were THE SAME, the chance of this
much evidence of a greater value for variable
Width (Old) than for variable Width (New)
would be approximately:
One-sided P-value = 0.1826.
The chance of this much evidence
in EITHER direction would be twice that
value, that is:
Two-sided P-value = 0.3653.
Inferences for the difference
in population means for,
Width
(Old) - Width (New)
are:
Estimate
Standard Error
0.912
1.003
Confidence limits
90% : -0.753002 to 2.577002
95% : -1.077787 to 2.901787
99% : -1.721973 to 3.545973
Student's t statistic
Degrees of freedom
0.910
98
Sample Means Standard
Error Sample Size
Width (Old)
86.0000
0.8978
50
Width (New)
85.0880
0.4465
50
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Based on this analysis, the process changes
did not result in a statistically significant
change in the mean. This conclusion is based
on the p-value, which is .3653. This can be
interpreted as indicating that we could observe
a difference of the size seen about 36% of the
time, even when there was no actual difference
in the means. The data does therefore not provide
enough evidence to conclude that the means are
different.
In a similar fashion, the hypothesis about
the variance of the data being the same is tested
using Statistics > One and Two-Sample Inference
> Two-Sample > Compare Dispersion. The
Width variable is tested against the Groups
defined by the Process variable ("Old"
versus "New").
Comparison of variances
for Variables:
Width (Old)
N = 50
Width (New)
N = 50
Width (Old) 130
Width (New)
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70
At least one of these samples is
quite skewed, and thus the population variances
may not be very useful as measures of dispersion.
It may be more useful to use this procedure
with the interquartile range option.
Alternatively, it might be better
to make some transformation of the data,
such as logarithmic, before this type of
analysis.
However, if one nevertheless wants
inference about the variances, the Levene
method used by this procedure is not highly
sensitive to lack of normality.
There is no significant
difference between the variances.
If in fact the populations
variances were THE SAME, the chance of this
much evidence of a greater value for variable:
Width (Old) than for variable:
Width (New) would be approximately:
One-sided P-value = 0.2348.
The chance of this much evidence
in EITHER direction would be twice that
value, that is:
Two-sided P-value = 0.4696.
This procedure uses as default
Levene's method, for both the test and confidence
intervals. The F-test, which is an
option, should not ordinarily be used for
this purpose.
Inferences for
the ratio of population standard deviations
for,
Width (Old) / Width (New)
are:
Estimate
Approx. Standard Error
2.011
0.284
Approximate Confidence Limits
90% : 0.721888 to 1.787993
95% : 0.627444 to 1.909192
99% : 0.441655 to 2.164697
Test of equal variance using Levene's method
Levene's t Statistic
Degrees of Freedom
0.726
98
One-sided P-value = 0.2348
Standard Deviations Approx.
Std. Error Sample Size
Width (Old)
6.3484
0.6348
50
Width (New)
3.1570
0.3157
50
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With this procedure we are testing the hypothesis
that the standard deviations from the two processes
are equal. Based on the two-sided p-value of
.4696, we cannot reject this hypothesis. Therefore,
the variance did not change when the process
changed.